Through what angle must a 0.2 MeV photon be scattered by a free electron in order for it to lose 10% of its energy?

Paloma Sanford

Paloma Sanford

Answered question

2022-10-23

Through what angle must a 0.2 MeV photon be scattered by a free electron in order for it to lose 10% of its energy?

Answer & Explanation

na1p1a2pafr

na1p1a2pafr

Beginner2022-10-24Added 16 answers

The fractional change in energy of a photon in Compton effect,
Energy of the photon, h v = 0.2  MeV
Energy lost, E = 10 % of its original energy
E = 10 % E
rest mass of the electron, m 0 = 0.511  MeV/c 2
θ = angle of scattering of the electron
E E = 10 100 = 0.1
using the formula, we get
E E = h v m 0 c 2 ( 1 cos θ ) 0.1 = 0.2 ( 0.511  MeV/c 2 ) c 2 ( 1 cos θ ) 0.1 = 0.2 0.511 ( 1 cos θ ) 1 0.2555 = cos θ cos θ = 0.7445 θ = 41.88
therefore the angle of scattering, θ = 41.88
Answer: required angle of scattering, θ = 41.88

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