Will Hodges

2023-03-11

A passenger plane made a trip to Las Vegas and back. On the trip there it flew 432 mph and on the return trip it went 480 mph. How long did the trip there take if the return trip took nine hours?

memorativl2f

Beginner2023-03-12Added 5 answers

Since the distance, d, traveled is the same for both trips,

$d=\left(480\text{mph}\right)\left(9\text{h}\right)=4320\text{miles}$

The time taken for the trip there, t, is the distance divided by the speed.

$t=\frac{4320\text{miles}}{432\text{mph}}=10\text{h}$

$d=\left(480\text{mph}\right)\left(9\text{h}\right)=4320\text{miles}$

The time taken for the trip there, t, is the distance divided by the speed.

$t=\frac{4320\text{miles}}{432\text{mph}}=10\text{h}$