How to solve goniometric equation where function arguments differ? cos 2 </msup>

Dale Tate

Dale Tate

Answered question

2022-06-21

How to solve goniometric equation where function arguments differ?
cos 2 x + cos 2 x + 1 = 0

Answer & Explanation

Cahokiavv

Cahokiavv

Beginner2022-06-22Added 31 answers

cos 2 x + cos 2 x + 1 = 0
cos 2 x + ( 2 cos 2 x 1 ) + 1 = 0
3 cos 2 x = 0
cos x = 0
x = π 2 , 3 π 2 . . .

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