A consumer in a grocery store pushes a cart with a force of 35 N directed at an angle of 25∘ below the horizontal. The force is just enough to overcome various frictional forces, so the cart moves at a steady pace. Find the work done by the shopper as she moves down a 50.0−m length aisle.??

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A consumer in a grocery store pushes a cart with a force of 35 N directed at an angle of 25∘ below the horizontal. The force is just enough to overcome various frictional forces, so the cart moves at a steady pace. Find the work done by the shopper as she moves down a 50.0−m length aisle.??

idoless0069w7r · Accepted Answer

To find the work done by the shopper as she moves down the aisle, we can use the formula for work:W=F·d·cos(θ)Where:W is the work done,F is the applied force,d is the distance, andθ is the angle between the force and the direction of motion.In this case, the applied force is 35 N and the distance is 50.0 m. The angle between the force and the direction of motion is 25 degrees below the horizontal.Substituting these values into the formula, we get:W=35N·50.0m·cos(25∘)To calculate the cosine of 25 degrees, we need to convert the angle to radians. We know that π radians is equal to 180 degrees, so we can convert 25 degrees to radians by multiplying it by π180:W=35N·50.0m·cos(25π180)Now, we can calculate the cosine of the angle:W=35N·50.0m·cos(25π180)≈35N·50.0m·0.90631Calculating the product of the force, distance, and cosine value:W≈1581.55N·m≈1581.55JFinally, we can convert the work from joules to kilojoules by dividing by 1000:W≈1581.55J1000≈1.58kJTherefore, the work done by the shopper as she moves down the 50.0 m length aisle is approximately 1.58kJ, which can be represented as Wman=1.58kJ.

A shopper in a supermarket pushes a cart with a force of 35 N directed

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