Find sin⁡(x)=12.

If ${\displaystyle \sin \left(x\right)=\frac{1}{2}=\sin \left(\frac{\pi }{6}\right)}$, so:
${\displaystyle x_1=\frac{\pi }{6}}$
${\displaystyle x_2=5\frac{\pi }{6}}$, that has the same value ${\displaystyle \left(\frac{1}{2}\right)}$
Since ${\displaystyle f\left(x\right)=\sin \left(x\right)}$ is a periodic function, with period ${\displaystyle 2\pi }$, there is an infinity if arcs that have the same sin value ${\displaystyle \left(\frac{1}{2}\right)}$, when the variable arc x rotates around the trig unit circle many times.
So,
${\displaystyle x=\frac{\pi }{6}+K\times 2\pi }$; and ${\displaystyle x=5\frac{\pi }{6}+K\times 2\pi }$, where K is a whole number.

${\displaystyle \sin 30°=\frac{1}{2}}$ and ${\displaystyle \sin 150°=\frac{1}{2}}$