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Trigonometric Functions
sagnuhh
2021-09-10
krolaniaN
Skilled2021-09-11Added 86 answers
limx→−2−f(x)=limx→−2−k+6x =k+6(−2) =k−12 limx→−2+f(x)=limx→−2+kx+9 =k(−2)+9 =−2k+9 For the function to be continuous: limx→−2−f(x)=limx→−2+f(x) Thus, k−12=−2k+9 3k=21 k=7
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