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$R={R}_{0}\ast (1+\alpha (T-{T}_{0}))$

Where ${R}_{0}$ and ${T}_{0}$ are the reference resistance and temperature.

Is it then safe to say that:

$\rho ={\rho}_{0}\ast (1+\alpha (T-{T}_{0}))$

(where ${\rho}_{0}$ is the reference resistivity)?

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