in number 7, Is the exponent of \((-1) n\) right? I thought that the exponent of (-1) is \(n-1\) because it changed from \(n=0\) to \(n=1\), and if \((-1)^{n}\), there will be a change of sign between negative sign and positive sign.

Simplify each of the following expressions. Be sure that your answer has no negative or fractional exponents. \(a\cdot(\frac{1}{81})^{-\frac{1}{4}}b\cdot x^{-2}y^{-4}c\cdot (2x)^{-2}(16x^{2y})^\frac{1}{2}\)

To find the equation: \(\int 2x\cos (3x)dx\)

Radical and Exponents Simplify the expression \((\frac{ab^2 c^{-3}}{2a^{3} b^{-4}})^{-2}\)

Simplify \(\sqrt{-54}\) using the imaginary number i A) \(\displaystyle{3}{i}\sqrt{{6}}\) B) \(\displaystyle-{3}\sqrt{{6}}\) C) \(\displaystyle{i}\sqrt{{54}}\) D) \(\displaystyle{3}\sqrt{-}{6}\)

To find the equation: \(\displaystyle{11}\cdot\sqrt{{48}}\)

prove that \(1+\tan h \frac{x}{1}-\tan hx = e^2x\)