Integration by parts to derive relativistic kinetic energy int^x_0 d/dt [m v gamma (v)]dx=v*mm v gamma(v)-int_0^v m v gamma(v) dv

Antwan Perez

Antwan Perez

Answered question

2022-10-20

Integration by parts to derive relativistic kinetic energy
0 x d d t [ m v γ ( v ) ] d x = v m v γ ( v ) 0 v m v γ ( v ) d v

Answer & Explanation

Bridget Acevedo

Bridget Acevedo

Beginner2022-10-21Added 19 answers

A little trick required here. Perform a substitution first:
m v γ ( v ) = u ,
hence your integral becomes
d u d t d x ,
but notice that
d u d t = d u d x d x d t d x ,
but d x d t = v - the definition of velocity! So the integral becomes:
d u d t d x = d u d x v d x .
So now you can just apply your general formula with no changes!
d u d x v d x = u v u d v .
Substituting for u get
d u d x v d x = m v γ ( v ) v m v γ ( v ) d v ,
QED.
Kymani Hatfield

Kymani Hatfield

Beginner2022-10-22Added 2 answers

You set the dot yourself. Plug in
d x = d x d t d t = v   d t ,
d v = d v d t d t
on the left and right hand side, respectively, and identify what is been differentiated with respect to t.

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