Systems of Linear Equations - Learn the Basics

Recent questions in Second order linear equations
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Ernstfalld Ernstfalld 2021-08-11

We give linear equations y=1.5x

Differential EquationsAnswered question
rocedwrp rocedwrp 2021-05-29

The integrating factor method, which was an effective method for solving first-order differential equations, is not a viable approach for solving second-order equstions. To see what happens, even for the simplest equation, consider the differential equation y+3y+2y=f(t). Lagrange sought a function μ(t)μ(t) such that if one multiplied the left-hand side of y+3y+2y=f(t) bu μ(t)μ(t), one would get μ(t)[y+y+y]=dddt[μ(t)y+g(t)y] where g(t)g(t) is to be determined. In this way, the given differential equation would be converted to ddt[μ(t)y+g(t)y]=μ(t)f(t), which could be integrated, giving the first-order equation μ(t)y+g(t)y=μ(t)f(t)dt+c which could be solved by first-order methods. (a) Differentate the right-hand side of μ(t)[y+y+y]=dddt[μ(t)y+g(t)y] and set the coefficients of y,y' and y'' equal to each other to find g(t). (b) Show that the integrating factor μ(t)μ(t) satisfies the second-order homogeneous equation μμ+μ=0 called the adjoint equation of y+3y+2y=f(t). In other words, althought it is possible to find an "integrating factor" for second-order differential equations, to find it one must solve a new second-order equation for the integrating factor μ, which might be every bit as hard as the original equation. (c) Show that the adjoint equation of the general second-order linear equation y+p(t)y+q(t)y=f(t) is the homogeneous equation μp(t)μ+[q(t)p(t)]μ=0.

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Ayaana Buck Ayaana Buck 2021-03-12

How to integrate cos2(2x)?

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slaggingV slaggingV 2021-03-11

(b)y+y+3.25=0

Dealing with second-order linear equations is quite complex for post-secondary algebra students who have to provide such equations for statistical analysis where calculus is involved. It’s a reason why linear equation examples help with the system of linear equations, especially when it has to be implemented in Sociology, Engineering, or even Business Management. It is a reason why linear equations word problems have also been offered below as students cannot approach them without some linear equations solver that would contain an explanation with details. You can see answers to questions and learn how linear equations and inequalities can be solved.