If a proton is accelerated from rest through a potential difference of 1250V find its approximate velocity at the end of this process.

2selz76t

2selz76t

Answered question

2022-12-17

If a proton is accelerated from rest through a potential difference of 1250V find its approximate velocity at the end of this process.

Answer & Explanation

Haven Boone

Haven Boone

Beginner2022-12-18Added 4 answers

work done = v q = 1260 ( 1.6 × 10 19 )
work done = final KE - initial kE ( but initial kE =0)
260 ( 1.6 × 10 19 ) = 1 2 ( 1.67 × 10 27 ) v 2 v 2 = 2414. 37 × 10 8 v = 49.13 × 10 4   m / s

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