Using matrix methods, how to find the image of the point (1,-2) for the transformations? 1) a dilation of factor 3 from the x-axis 2) reflection in the x-axis

Name: Using matrix methods, how to find the image of the point (1,-2) for the transformations? 1) a dilation of factor 3 from the x-axis 2) reflection in the x-axis
Uploaded: 2022-02-23T17:22:57+00:00
Description: Using matrix methods, how to find the image of the point (1,-2) for the transformations? 1) a dilation of factor 3 from the x-axis 2) reflection in the x-axis

Question

Tamia Padilla · Accepted Answer

MathJax(?): Can&#039;t find handler for document MathJax(?): Can&#039;t find handler for document 1) multiply the coordinates by the scale factor      &amp;#x21D2;          (                                    x            &amp;#x2032;                                                y            &amp;#x2032;                              )        =                  3                    (                                    1                                                -            2                              )        =          (                                    3                                                -            6                              )            &amp;#x21D2;          (      1      ,      -      2      )        &amp;#x2192;          (      3      ,      -      6      )      2) multiply by the associated reflection matrixfor reflection in the x-axis      &amp;#x2022;                  x                    (                                    1                                0                                                0                                -            1                              )            &amp;#x21D2;          (                                    x            &amp;#x2032;                                                y            &amp;#x2032;                              )        =          (                                    1                                0                                                0                                -            1                              )              (                                    x                                                y                              )          =          (                                    1                                0                                                0                                -            1                              )              (                                    1                                                -            2                              )        =          (                                    1                                                2                              )            &amp;#x21D2;          (      1      ,      -      2      )        &amp;#x2192;          (      1      ,      2      )