Different way to determine rank of 3\times3 -matrix with parameter

Lainey Goodwin

Lainey Goodwin

Answered question

2022-01-30

Different way to determine rank of 3×3 -matrix with parameter by using row transformations
A=(2a1aa1a1a022a1a(1a)).

Answer & Explanation

Dominique Green

Dominique Green

Beginner2022-01-31Added 11 answers

Step 1 You can simplify algorithm, borrowing techniques used for the computation of determinants: [2a1aa1a1a022a1a(1a)][1a1a022a1a(1a)2a1aa] Now, if a1 this matrix has the same rank as [1100112a1aa][11001101a][11001100a+1]. You can now conclude (not forgetting to examine the case a=1).
waijazar1

waijazar1

Beginner2022-02-01Added 13 answers

Gauss is very comfortable here; just switch column two and one. Consider then the case a=1; here the rank is 1. Otherwise you will be done in two very easy steps without considering further cases.

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