Considering the curvature of the Earth (R is the Earth radius) and a non-vertical direction (zenith angle theta), the relation between h and path length L in the atmosphere is: h=L cos theta+1/2 (L^2)/(R) sin^2 theta

charmbraqdy

charmbraqdy

Answered question

2022-11-18

I'm having trouble obtaining this formula.
Considering the curvature of the Earth (R is the Earth radius) and a non-vertical direction (zenith angle θ ), the relation between h and path length L in the atmosphere is:
h = L cos θ + 1 2 L 2 R sin 2 θ
h is the atmosphere's height.
I understand the first term (which due to the inclination) but I can't find a way to get the second term (which is introduced by considering the "roundness" of the Earth)
Any help would be greatly appreciated

Answer & Explanation

Miah Carlson

Miah Carlson

Beginner2022-11-19Added 17 answers

On the triangle formed by the point of entry of the light ray into the atmosphere (we assume the atmosphere is a sphere of finite radius), the point of observation and the Earth's center we can apply the law of cosines to find that
h = R 2 + L 2 + 2 L R cos θ R
We can Taylor expand this function in powers of L / R assuming that L R (which means the Earth is very big compared to it's atmosphere so it's approximately flat). Keeping terms up to quadratic order we find
h = L cos θ + L 2 2 R sin 2 θ + O ( L 3 R 2 )

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