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2023-02-19

The frequency of yellow light having wavelength 600 nm is

$A)5.0\times {10}^{14}\text{}Hz;\phantom{\rule{0ex}{0ex}}B)2.5\times {10}^{7}\text{}Hz;\phantom{\rule{0ex}{0ex}}C)5.0\times {10}^{7}\text{}Hz;\phantom{\rule{0ex}{0ex}}D)2.5\times {10}^{14}\text{}Hz$

$A)5.0\times {10}^{14}\text{}Hz;\phantom{\rule{0ex}{0ex}}B)2.5\times {10}^{7}\text{}Hz;\phantom{\rule{0ex}{0ex}}C)5.0\times {10}^{7}\text{}Hz;\phantom{\rule{0ex}{0ex}}D)2.5\times {10}^{14}\text{}Hz$

Adrienne Clark

Beginner2023-02-20Added 9 answers

The ideal decision is A

$5.0\times {10}^{14}\text{}Hz$

We are aware that all electromagnetic radiation moves at the speed of light in a vacuum.

$c=\nu \lambda $

$\nu =\frac{c}{\lambda}=\frac{3\times {10}^{8}\text{}m/s}{600\times {10}^{-9}\text{}m}=5.0\times {10}^{14}\text{}Hz$

$5.0\times {10}^{14}\text{}Hz$

We are aware that all electromagnetic radiation moves at the speed of light in a vacuum.

$c=\nu \lambda $

$\nu =\frac{c}{\lambda}=\frac{3\times {10}^{8}\text{}m/s}{600\times {10}^{-9}\text{}m}=5.0\times {10}^{14}\text{}Hz$