A 10.0 g marble slides to the left with a velocity ofmagnitude 0.300 m/s on thefrictionless, horizontal surface of an icy, New York sidewalk andhas a head-on elastic collision with a larger 25.0 g marble sliding to the right with a velocityof magnitude 0.150 m/s (Fig. 8.35).&nbsp;(a) Find the velocity of each marble (magnitude anddirection) after the collision. (Since the collision is head-on,all the motion is along a line. Take right as the positivex direction.)&nbsp;m/s (smaller marble)&nbsp;m/s (larger marble)&nbsp;(b) Calculate the change in momentum (that is, the momentum afterthe collision minus the momentum before the collision) for eachmarble.&nbsp;kgm/s (smallermarble)&nbsp;kgm/s (largermarble)&nbsp;(c) Calculate the change in kinetic energy (that is, the kineticenergy after the collision minus the kinetic energy before thecollision) for each marble.&nbsp;J (smaller marble)&nbsp;J (larger marble)

Question

A 10.0 g marble slides to the left with a velocity ofmagnitude 0.300 m/s on thefrictionless, horizontal surface of an icy, New York sidewalk andhas a head-on elastic collision with a larger 25.0 g marble sliding to the right with a velocityof magnitude 0.150 m/s (Fig. 8.35).&amp;nbsp;(a) Find the velocity of each marble (magnitude anddirection) after the collision. (Since the collision is head-on,all the motion is along a line. Take right as the positivex direction.)&amp;nbsp;m/s (smaller marble)&amp;nbsp;m/s (larger marble)&amp;nbsp;(b) Calculate the change in momentum (that is, the momentum afterthe collision minus the momentum before the collision) for eachmarble.&amp;nbsp;kgm/s (smallermarble)&amp;nbsp;kgm/s (largermarble)&amp;nbsp;(c) Calculate the change in kinetic energy (that is, the kineticenergy after the collision minus the kinetic energy before thecollision) for each marble.&amp;nbsp;J (smaller marble)&amp;nbsp;J (larger marble)

Talisha · Accepted Answer

A. Mass of the first marble m1=25g Initial velocity of the first marble u1=0.15m/s Mass of the second marble m2=10g Initial velocity of the second marble u2=−0.3m/s a) Then ν1=((m1−m2)(m1+m2))u1+(2m2m1+m2u2) ν2=(2m1m1+m2)u1+(m1−m2m1+m2)u2 b) Initial momentum p1=m1u1+m2u2 final momentum p2=m1ν1+m2ν2 Change in momentum is the difference between the two momenta c) Kinetic energy KE=12mν2 Find the total kinetic energy of the system before and after collisionand find the difference.

A 10.0 g marble slides to the left with a velocity ofmagnitude 0.300 m/s on thefrictionless, horizontal surface of an icy, New York sidewalk andhas a

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