Find both first partial derivatives. f(x,y)=x2−2y2+4

Alyce Wilkinson

Alyce Wilkinson

Answered

2020-11-23

Find both first partial derivatives.
f(x,y)=x22y2+4

Answer & Explanation

Leonard Stokes

Leonard Stokes

Expert

2020-11-24Added 98 answers

Step 1
we have to find the first partial derivatives:
the given function is:
f(x,y)=x22y2+4
Step 2
fx=(x22y2+4)x
=x2x2x2x+4x
=2x2(0)+0
=2x0+0=2x
fy=(x22y2+4)y
=x2y2y2y+4y
=02y2y+0
=2(2y)=4y
Step 3
therefore the value of both first partial derivatives is:
fx=2x
fy=4y

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?