What are the vertices of 9x^2+16y^2=144?

hor1paeeja

hor1paeeja

Answered question

2023-03-25

What are the vertices of 9 x 2 + 16 y 2 = 144 ?

Answer & Explanation

dalematealreypq3a

dalematealreypq3a

Beginner2023-03-26Added 10 answers

9 x 2 + 16 y 2 = 144
Divide each term by 144 .
9 x 2 144 + 16 y 2 144 = 144 144
Simplify
x 2 16 + y 2 9 = 1
The major axis is the x-axis because the largest denominator is under the x 2 term.
The vertices' coordinates are as follows ...
( ± a , 0 )
( 0 , ± b )
a 2 = 16 a = 4
b 2 = 4 b = 2
( ± 4 , 0 )
( 0 , ± 2 )

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