How to find all the critical points to graph x^2 - y^2 + 9 = 0 including vertices, foci and asymptotes?

wabennestvzz

wabennestvzz

Answered question

2023-01-31

How to find all the critical points to graph x 2 - y 2 + 9 = 0 including vertices, foci and asymptotes?

Answer & Explanation

Natalia Arroyo

Natalia Arroyo

Beginner2023-02-01Added 4 answers

x 2 - y 2 + 9 = 0 or y 2 - x 2 = 9 or
y 2 3 2 - x 2 3 2 = 1 .The common vertical equation
hyperbola is ( y - k ) 2 a 2 - ( x - h ) 2 b 2 = 1 ; h , k being center.
Here h = 0 , k = 0 , a = 3 , b = 3 . So center is at ( 0 , 0 )
Vertices are a = 3 units from center . Therefore two vertices
are at ( 0 , 3 ) and ( 0 , - 3 ) , Focii are c units from center.
c 2 = a 2 + b 2 = 9 + 9 = 18 c = 3 2 . Therefore focii are
( 0 , 3 2 ) and ( 0 , - 3 2 ) . Hyperbola has two asymptotes
that intersect at the center of the hyperbola. The asymptotes
pass through the vertices of a rectangle of dimensions
2 a = 6 and 2 b = 6 with its center at ( 0 , 0 )
slope ± a b = ± 1 . Equation of asymptotes are
y - 0 = ± 1 ( x - 0 ) or y = ± x
graph{x^2-y^2+9=0 [-10, 10, -5, 5]}

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?