What is the probability of 130 or more successes ( to 4 decimals)&nbsp;

Question

What is the probability of 130 or more successes ( to 4 decimals)&amp;nbsp;

Eliza Beth13 · Accepted Answer

If we assume that the number of successes follows a binomial distribution, where there are a fixed number of trials and each trial has a constant probability of success, we can use the binomial probability formula.
Let's suppose we have a binomial distribution with parameters

n

(number of trials) and

p

(probability of success in each trial). The probability of obtaining

k

successes in

n

trials is given by the binomial probability formula:

P (X = k) = (\binom{n}{k}) \cdot p^{k} \cdot (1 - p)^{n - k}

In this formula,

(\binom{n}{k})

represents the number of combinations of

n

trials taken

k

at a time.
To find the probability of 130 or more successes, we would need to sum the probabilities of getting 130, 131, 132, and so on, up to the maximum possible number of successes. However, this calculation requires the values of

n

and

p

specific to the problem.

What is the probability of 130 or more

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