A local newspaper in a large city wants to assess support for the construction of...

umthumaL3e

umthumaL3e

Answered

2022-12-03

A local newspaper in a large city wants to assess support for the construction of a highway bypass around the central business district to reduce downtown traffic. They survey a random sample of 1152 residents and find that 543 of them support the bypass. Construct and interpret a 95% confidence interval to estimate the proportion of residents who support construction of the bypass.

Answer & Explanation

kriteria0b1

kriteria0b1

Expert

2022-12-04Added 10 answers

given that,
possible chances (x)=543
size(n)=1152
success rate ( p )= x/n = 0.4714
point of estimate = proportion = 0.4714
standard error = ( 0.4714 0.5286 ) 1152
= 0.0147
margin of error = Z a 2 (standard error)
where,
Z a 2 = Z-table value
level of significance, α = 0.05
from standard normal table, two tailed z α 2 = 1.96
margin of error  = 1.96 0.0147
= 0.0288
C I = [ p ±  margin of error ]
confidence interval  = [ 0.4714 ± 0.0288 ]
= [ 0.4425 , 0.5002 ]

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