Let a be the two dimensional vector <-2, 4>

Consider a general vector $b\ne 0$ whose position vector makes an angle $\theta $ withthe x-axis.

Explain why, no matter what b is, the tip of the positionvector of $\frac{b}{|b|}$ is on the unit circle.

Consider a general vector $b\ne 0$ whose position vector makes an angle $\theta $ withthe x-axis.

Explain why, no matter what b is, the tip of the positionvector of $\frac{b}{|b|}$ is on the unit circle.