# Let a be the two dimensional vector <-2, 4> Consider a general vector b ne 0 whose position vector makes an angle theta with the x-axis. Explain why, no matter what b is, the tip of the position vector of b/(|b|) is on the unit circle.

Let a be the two dimensional vector <-2, 4>
Consider a general vector $b\ne 0$ whose position vector makes an angle $\theta$ withthe x-axis.
Explain why, no matter what b is, the tip of the positionvector of $\frac{b}{|b|}$ is on the unit circle.
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uavklarajo
$\frac{b}{|b|}$ in terms of magnitude =1 { Any vector divided by its magnitude equals 1 (unit vector) }
the radius of a unit circle also = 1
therefore the tip of $\frac{b}{|b|}$ must lie on the unit circle.
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