Find a unit vector parallel to the vector y=<1,-2,2> which points in the opposite direction.

Find a unit vector parallel to the vector y=<1,-2,2> which points in the opposite direction.
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Izabelle Frost
y=<1,-2,2>=v
$\frac{v}{|v|}=\frac{<1,-2,2>}{|<1,-2,2>|}=\frac{<1,-2,2>}{\sqrt{{1}^{2}+\left(-2{\right)}^{2}+{2}^{2}}}=\frac{<1,-2,2>}{\sqrt{1+4+4}}=\frac{<1,-2,2>}{\sqrt{9}}=\frac{<1,-2,2>}{3}$
a unit vector that is parallel to the vector y and is in the same direction
$<\frac{1}{3},\frac{-2}{3},\frac{2}{3}>$
to make it going in the opposite directi on, we multiply the unit vector by a scalar -1
$\left(-1\right)<\frac{1}{3},\frac{-2}{3},\frac{2}{3}>=<\frac{-1}{3},\frac{2}{3},\frac{-2}{3}>$
$<\frac{-1}{3},\frac{2}{3},\frac{-2}{3}>$
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Awainaideannagi
The unit vector would be 1/3(-1,2,-2)