If it takes 10.2 eV of energy excite hydrogen from the ground state into the first excited (n = 2) state, then what frequency photon is required to excite hydrogen out of the ground state into n = 2 state? What is the wavelength (lambda) of that photon? What kind of radiation (region of the electromagnetic spectrum) is this photon?

Donna Flynn 2022-07-17 Answered
If it takes 10.2 eV of energy excite hydrogen from the ground state into the first excited (n = 2) state, then what frequency photon is required to excite hydrogen out of the ground state into n = 2 state? What is the wavelength ( λ) of that photon? What kind of radiation (region of the electromagnetic spectrum) is this photon?
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Answers (1)

frisiao
Answered 2022-07-18 Author has 13 answers
The energy difference between the ground state and the first excited state is Δ E = h v         [ 1 ]
Use equation (1) to solve for the frequency of the photon.
v = Δ E h = 10.2 e V × 1.6 × 10 19   J 1 e V 6.626 × 10 34   J s = 2.463 × 10 15 [ 2 ]
The wavelength of the photon is
λ = c v = 3 × 10 8   m / s 2.463 × H z = 1.218 × 10 7   m [ 3 ]
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