If an object has very energetic particles in it like that of the sun then wouldn't its mass be higher hence making its gravity greater than that of the still state ones ?

Ishaan Booker
2022-07-15
Answered

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asked 2022-05-19

Does a relativistic version of quantum thermodynamics exist? I.e. in a non-inertial frame of reference, can I, an external observer, calculate quantities like magnetisation within the non-inertial frame?

asked 2022-07-13

It is experimentally known that the equation of motion for a charge $e$ moving in a static electric field $\mathbf{E}$ is given by:

$\frac{\mathrm{d}}{\mathrm{d}t}(\gamma m\mathbf{v})=e\mathbf{E}$

Is it possible to show this using just Newton's laws of motion for the proper frame of $e$, symmetry arguments, the Lorentz transformations and other additional principles?

$\frac{\mathrm{d}}{\mathrm{d}t}(\gamma m\mathbf{v})=e\mathbf{E}$

Is it possible to show this using just Newton's laws of motion for the proper frame of $e$, symmetry arguments, the Lorentz transformations and other additional principles?

asked 2022-08-12

Is it allowed to have the zeroth-component of a four-velocity be negative?

This is referring to $V^0$ for a curved space metric with signature $-+++$.

This is referring to $V^0$ for a curved space metric with signature $-+++$.

asked 2022-08-20

Suppose we have an integral $\int {\mathrm{d}}^{4}k\phantom{\rule{thinmathspace}{0ex}}\text{}f(k)$

we want to evaluate and that we're in Minkowski space with some metric $(+,-,-,-)$.

Is it true that:

${\mathrm{d}}^{4}k=\mathrm{d}{k}^{0}\text{}{\mathrm{d}}^{3}\mathbf{k}=\mathrm{d}{k}^{0}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}|\mathbf{k}{|}^{2}\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}|\mathbf{k}|\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}(\mathrm{cos}\theta )\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}\varphi $

just like in ordinary space?

we want to evaluate and that we're in Minkowski space with some metric $(+,-,-,-)$.

Is it true that:

${\mathrm{d}}^{4}k=\mathrm{d}{k}^{0}\text{}{\mathrm{d}}^{3}\mathbf{k}=\mathrm{d}{k}^{0}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}|\mathbf{k}{|}^{2}\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}|\mathbf{k}|\phantom{\rule{thinmathspace}{0ex}}\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}(\mathrm{cos}\theta )\phantom{\rule{thinmathspace}{0ex}}\mathrm{d}\varphi $

just like in ordinary space?

asked 2022-07-14

If the velocity is a relative quantity, will it make inconsistent equations when applying it to the conservation of energy equations?

For example:

In the train moving at $V$ relative to ground, there is an object moving at $v$ relative to the frame in the same direction the frame moves. Observer on the ground calculates the object kinetic energy as $\frac{1}{2}m(v+V{)}^{2}$. However, another observer on the frame calculates the energy as $\frac{1}{2}m{v}^{2}$.

For example:

In the train moving at $V$ relative to ground, there is an object moving at $v$ relative to the frame in the same direction the frame moves. Observer on the ground calculates the object kinetic energy as $\frac{1}{2}m(v+V{)}^{2}$. However, another observer on the frame calculates the energy as $\frac{1}{2}m{v}^{2}$.

asked 2022-08-11

If some kind of source was able to supply an infinite amount of energy, does that imply that it also must have an infinite mass? Is the contrary also true?

asked 2022-08-11

If light travels at the speed of light, and anything with rest mass will experience relativistic effects based on the Lorentzian equations, why doesn't light experience these kinds of effects?

For example, relativistic mass and rest mass are related via

$m = \frac{m_0}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Shouldn't light therefore have no rest mass (since the Lorentzian is $0$)?

For example, relativistic mass and rest mass are related via

$m = \frac{m_0}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Shouldn't light therefore have no rest mass (since the Lorentzian is $0$)?