Evaluating <munder> <mo movablelimits="true" form="prefix">lim <mrow class="MJX-TeXAto

Lucia Grimes

Lucia Grimes

Answered question

2022-07-12

Evaluating lim x 0 2 cos ( a + x ) cos ( a + 2 x ) cos ( a ) x 2

Answer & Explanation

Elianna Wilkinson

Elianna Wilkinson

Beginner2022-07-13Added 11 answers

HINT:
Using Prosthaphaeresis Formula,
cos ( a + 2 x ) + cos a = 2 cos ( a + x ) cos x
Now 1 cos x x 2 = ( sin x x ) 2 1 1 + cos x

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