The vectors {u, v, w} are linearly independent.

Богдан Худояров

Богдан Худояров

Answered question

2022-05-29

The vectors {u, v, w} are linearly independent. Determine, using the definition, whether the vectors {v, u v w, u 2v 2w} are linearly independent.

Answer & Explanation

Don Sumner

Don Sumner

Skilled2023-05-18Added 184 answers

To determine whether the vectors v,u,v+w,u+2v+2w are linearly independent, we need to check if the only solution to the equation:
a1v+a2u+a3(v+w)+a4(u+2v+2w)=0
where a1,a2,a3,a4 are scalars, is the trivial solution a1=a2=a3=a4=0.
Expanding the equation, we have:
a1v+a2u+a3v+a3w+a4u+2a4v+2a4w=0
Rearranging the terms, we get:
(a1+a3+a4)v+(a2+a4)u+(a3+2a4)w=0
For the vectors {v, u, w} to be linearly independent, the coefficients of v, u, and w must all equal zero. Therefore, we have the following system of equations:
a1+a3+a4=0
a2+a4=0
a3+2a4=0
We can solve this system of equations to find the values of a1,a2,a3,a4.
To do this, we can express the system of equations in matrix form:
[101101010012][a1a2a3a4]=[000]
To find the solution to this system, we need to row-reduce the augmented matrix:
[101101010012][100101010012]
The row-reduced form of the matrix indicates that the system has a unique solution. Therefore, the only solution to the system is a1=1, a2=1, a3=2, a4=0.
Since the solution is not the trivial solution, it means that the vectors {v, u, v + w, u + 2v + 2w} are linearly dependent.

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