How do you calculate the absolute index of refraction?

Ainsley Zimmerman
2022-05-10
Answered

How do you calculate the absolute index of refraction?

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garcialdariamcy4q

Answered 2022-05-11
Author has **15** answers

Absolute refractive index is the refractive index when a light ray passes from air to the given medium or from a medium to air.

We thus apply Snell's law as follows(for a ray going from air to a medium),

${n}_{a}\mathrm{sin}i={n}_{m}\mathrm{sin}r$

where ${n}_{m}$ is the refractive index of the medium

${n}_{a}$ is the refractive index of air

i is the angle of incidence

r is the angle of refraction

Make ${n}_{m}$ the subject in the above equation

$\Rightarrow {n}_{m}=\frac{{n}_{a}\mathrm{sin}i}{\mathrm{sin}r}$

${n}_{a}=1$

$\Rightarrow {n}_{m}=\frac{\mathrm{sin}i}{\mathrm{sin}r}$

Also, another definition says that ${n}_{m}=\frac{c}{{c}_{m}}=\frac{speed\text{}of\text{}light\text{}in\text{}vacuum}{speed\text{}of\text{}light\text{}in\text{}the\text{}medium}$

We thus apply Snell's law as follows(for a ray going from air to a medium),

${n}_{a}\mathrm{sin}i={n}_{m}\mathrm{sin}r$

where ${n}_{m}$ is the refractive index of the medium

${n}_{a}$ is the refractive index of air

i is the angle of incidence

r is the angle of refraction

Make ${n}_{m}$ the subject in the above equation

$\Rightarrow {n}_{m}=\frac{{n}_{a}\mathrm{sin}i}{\mathrm{sin}r}$

${n}_{a}=1$

$\Rightarrow {n}_{m}=\frac{\mathrm{sin}i}{\mathrm{sin}r}$

Also, another definition says that ${n}_{m}=\frac{c}{{c}_{m}}=\frac{speed\text{}of\text{}light\text{}in\text{}vacuum}{speed\text{}of\text{}light\text{}in\text{}the\text{}medium}$

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