How can you compare the two confidence intervals i.e 90% and 99%?

2022-04-18
Answered

How can you compare the two confidence intervals i.e 90% and 99%?

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star233

Answered 2022-06-20
Author has **208** answers

A 99 percent confidence interval would be wider than a 95 percent confidence interval (for example, plus or minus 4.5 percent instead of 3.5 percent). A 90 percent confidence interval would be narrower (plus or minus 2.5 percent, for example).

asked 2020-12-30

A majorette in a parade is performing some acrobatic twirlingsof her baton. Assume that the baton is a uniform rod of mass 0.120 kg and length 80.0 cm.

With a skillful move, the majorette changes the rotation ofher baton so that now it is spinning about an axis passing throughits end at the same angular velocity 3.00 rad/s as before. What is the new angularmomentum of the rod?

asked 2022-06-24

Given the first-order differential equation:

$\frac{dy}{dx}=-6xy$

The textbook says you cannot differentiate both sides as y is on the right side and you have to use separation of variables. However, I did integrate both sides and arrived at this:

$\int \frac{dy}{dx}dx=\int -6xydx$

$y=-6y\int xdx$

$y=-6y(\frac{{x}^{2}}{2}+C)$

$y=-3y{x}^{2}+C$

$y+3y{x}^{2}=C$

$y(1+3{x}^{2})=C$

$y(x)=\frac{C}{1+{x}^{2}}$

And the second last step is valid since $1+3{x}^{2}$ can never be zero. However, this is not the correct answer, which is:

$y(x)=C{e}^{-3{x}^{2}}$. Why is this?

$\frac{dy}{dx}=-6xy$

The textbook says you cannot differentiate both sides as y is on the right side and you have to use separation of variables. However, I did integrate both sides and arrived at this:

$\int \frac{dy}{dx}dx=\int -6xydx$

$y=-6y\int xdx$

$y=-6y(\frac{{x}^{2}}{2}+C)$

$y=-3y{x}^{2}+C$

$y+3y{x}^{2}=C$

$y(1+3{x}^{2})=C$

$y(x)=\frac{C}{1+{x}^{2}}$

And the second last step is valid since $1+3{x}^{2}$ can never be zero. However, this is not the correct answer, which is:

$y(x)=C{e}^{-3{x}^{2}}$. Why is this?

asked 2022-06-29

What does "spread of momentum" actually mean?

I was reading Feynman's lecture in which Feynman invoked his own way of explaining the uncertainty principle using single-slit experiment.

There I found:

To get a rough idea of the spread of momentum, the vertical momentum ${p}_{y}$ has a spread which is equal to ${p}_{0}\mathrm{\Delta}\theta $, where ${p}_{0}$ is the horizontal momentum . . .

What is he talking of? What does "spreading" actually mean? And how did he measure it?

I was reading Feynman's lecture in which Feynman invoked his own way of explaining the uncertainty principle using single-slit experiment.

There I found:

To get a rough idea of the spread of momentum, the vertical momentum ${p}_{y}$ has a spread which is equal to ${p}_{0}\mathrm{\Delta}\theta $, where ${p}_{0}$ is the horizontal momentum . . .

What is he talking of? What does "spreading" actually mean? And how did he measure it?

asked 2022-05-07

What is half life decay?

asked 2020-11-30

Find the x-and y-intercepts of the graph of the equation algebraically.

$y=-5x+6$

asked 2021-10-15

Use the deffinition of derivatives to deffrintiate $y=-{x}^{3}+3x-6$

asked 2021-02-12

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point.
$x=3\text{}\mathrm{ln}(t),\text{}y=4{t}^{\frac{1}{2}},\text{}z={t}^{3},\text{}(0,\text{}4,\text{}1)$