The line through the point&nbsp;(1,0,6)(1,0,6) and perpendicular to the plane&nbsp;x+3y+z=5x+3y+z=5 has vector equation&nbsp;underline{r}=langle u,v,w rangle =langle a,b,c rangle + t langle d,e,f rangler=⟨u,v,w⟩=⟨a,b,c⟩+t⟨d,e,f⟩, with&nbsp;t in mathbb{R}t∈R.&nbsp;

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Bonolo Kgomoeswana

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2022-11-05

The line through the point $(1,0,6)$ (1,0,6) and perpendicular to the plane $x+3y+z=5$ x+3y+z=5 has vector equation $\underline{r}=\langle u,v,w \rangle =\langle a,b,c \rangle + t \langle d,e,f \rangle$ r=⟨u,v,w⟩=⟨a,b,c⟩+t⟨d,e,f⟩, with $t \in \mathbb{R}$ t∈R.

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