Abelian group order divides 1cm I want to prove the following: Let G be an abelian group an

Kamari Simon

Kamari Simon

Answered question

2022-02-15

Abelian group order divides 1cm
I want to prove the following:
Let G be an abelian group and let a1,,arG then |a1ar| (the order of a1ar) divides 1cm(|a1|,,|ar|)
So far I have shown that (a1,,ar)1cm(|a1|,,|ar|)=1 but I dont

Answer & Explanation

Anahi Pearson

Anahi Pearson

Beginner2022-02-16Added 16 answers

It does imply the desired result. Note that if an=1, then |a| divides n. Simply write n=|a|q+r for 0r<|a|, and then
1=an=a|a|qar=1qar=ar,
and so since r<|a| and ar=1, we have r=0.

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