Find invariant points under matrix transformation The matrix: \(Q=\begin{bmatrix}-1&2\\0&1\\\end{bmatrix}\)

Miguel Davenport 2022-01-30 Answered
Find invariant points under matrix transformation
The matrix:
Q=[1201]
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Expert Answer

Nevaeh Jensen
Answered 2022-01-31 Author has 14 answers
Step 1
Q has rank 2 and eigenvalues +1 and -1. The invariant points correspond to the eigenvectors with eigenvalue +1. As you have found, these are scalar multiples of
[11]
and so lie on the line y=x.
The eigenvectors with eigenvalue -1 are scalar multiples of
[10]
and so lie on the line y=0. In other words, points on the x axis are reflected in the y axis.
If λ is an eigenvalue of Q then det(QλI)=0, in other words QλI is degenerate. So when you solve
(QλI)X=0 to find the eigenvector for a given eigenvalue, the final row of (QλI)X is always redundant.

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Jason Duke
Answered 2022-02-01 Author has 11 answers
Step 1
The non-zero invariant points are eigenvectors with eigenvalue 1. If the problem has full rank, then the only solution would be the zero vector.
As you have shown, the only condition is x=y. That is, the invariant points are multiples of
[11].

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