What is the domain and range of y=\arcsin x

What is the domain and range of $$\displaystyle{y}={\arcsin{{x}}}$$

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Mary Herrera
Range: -pi/2 ≤ y ≤ pi/2
Domain: -1 ≤ x ≤ 1
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The original sine function defined for any real argument does not have an inverse function because it does not establish a one-to-one correspondence between its domain and a range.
To be able to define an inverse function, we have to reduce the original definition of a sine function to an interval where this correspondence does take place. Any interval where sine is monotonic and takes all values in its range would fit this purpose.
For a function $$y=\sin x$$ an interval of monotonic behavior is usually chosen as $$[-\frac{\pi}{2},\frac{\pi}{2}],$$ where the function is monotonously increasing from -1 to 1.
This variant of a sine function, reduced to an interval where it is monotonous and fills an entire range, has an inverse function called $$y=\arcsin (x)$$
It has range $$[-\frac{\pi}{2},\frac{\pi}{2}]$$ and domain from -1 to 1