Why does \sec(\frac{\pi}{4})=\sqrt{2}?

Why does $\mathrm{sec}\left(\frac{\pi }{4}\right)=\sqrt{2}$?
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Explanation:
$\mathrm{sec}\left(\frac{\pi }{4}\right)=\frac{1}{\mathrm{cos}\left(\frac{\pi }{4}\right)}$
Trig Table of Special arcs gives --> $\mathrm{cos}\left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$
Therefore
$\mathrm{sec}\left(\frac{\pi }{4}\right)=\frac{2}{\sqrt{2}}=\sqrt{2}$
amarantha41