# How do you solve \cos(x)=\frac{1}{2}

How do you solve $\mathrm{cos}\left(x\right)=\frac{1}{2}$
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Esther Phillips

$\mathrm{cos}\left(x\right)>0$
And x will be in the first/fourth quadrants
$\mathrm{cos}\left(x\right)=\frac{1}{2}$
$x={\mathrm{cos}}^{-1}\left(\frac{1}{2}\right)=\frac{\pi }{3}$ is an angle in the first quadrant.
$x=\left(2\pi -\frac{\pi }{3}\right)=\frac{5\pi }{3}$ is an angle in the fourth quadrant.

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soanooooo40
General solutions for $\mathrm{cos}\left(x\right)=\frac{1}{2}$ are:
$x=\frac{\pi }{3}+2\pi n$ and $x=\frac{5\pi }{3}+2\pi n$