Help to solve the triangle ABC, given a=22, A=50, c=27.

Help to solve the triangle ABC, given a=22, A=50, c=27.

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Fommeirj
We have to find th third side and two other angles.
PSK\sin C=\frac{c\sin A}{a}=\frac{27\sin50}{22}=0.9401
$$\displaystyle{C}={{\sin}^{{-{1}}}{0.9401}}={70}°$$
$$\displaystyle{B}={180}°-{50}°-{70}°={60}°$$
$$\displaystyle{b}={\frac{{{a}{\sin{{B}}}}}{{{\sin{{A}}}}}}={\frac{{{22}\times{\sin{{60}}}°}}{{{\sin{{50}}}°}}}={24.87}$$