Question: "Find derivatives of r=(0−1)(02+0+1)03" - Plainmath

texelaare

Answered question

2021-09-23

Find derivatives of

r = \frac{(0 - 1) (0^{2} + 0 + 1)}{0^{3}}

Answer & Explanation

crocolylec

Skilled2021-09-24Added 100 answers

Step 1 Given function

r = \frac{(0 - 1) (0^{2} + 0 + 1)}{0^{3}}

Step 2 Formula

\frac{d}{d x} (\frac{u}{v}) = \frac{v u^{'} - u v^{'}}{v^{2}}

Step 3 Solution to the question

r = \frac{(0^{3} - 1)}{0^{3}} [(a^{3} - b^{3}) = (a - b) (a^{2} + a b + b^{2})]

r^{'} = \frac{0^{3} (30^{2} - (30^{2}) (0^{3} - 1))}{0^{6}}

r^{'} = \frac{30^{5} - 30^{5} + 30^{2}}{0^{6}}

r^{'} = \frac{30^{2}}{0^{6}}

r^{'} = \frac{3}{0^{4}}

Step 4 Answer

r^{'} = \frac{3}{0^{4}}

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