# Given a right triangle with anglea=65^circ. The cathetus opposite to angle a is barA=250 m. Find the second cathetus (barB).

Given a right triangle with $$\displaystyle\angle{a}={65}^{\circ}$$. The cathetus opposite to $$\displaystyle\angle$$a is $$\displaystyle\overline{{A}}={250}$$ m. Find the second cathetus $$\displaystyle{\left(\overline{{B}}\right)}$$.

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

### Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Leonard Stokes
Since it's a right triangle, use the tanget ratio:
$$\displaystyle{\tan{{\left(\angle\right)}}}=\frac{{\overline{{{o}{p}{p}}}}}{{\overline{{{a}{d}{j}}}}}$$
Substitute values from the given:
$$\displaystyle{{\tan{{65}}}^{\circ}=}\frac{{250}}{\overline{{B}}}$$
Isolate $$\displaystyle\overline{{B}}$$:
$$\displaystyle\overline{{B}}=\frac{{250}}{{{\tan{{65}}}^{\circ}}}$$
$$\displaystyle\overline{{B}}\approx{116.6}$$ m