Find the derivatives of y with respect to the appropriate variable. y=x\sin ^{-1}x+\sqrt{1}=x^{2}

Trent Carpenter

Trent Carpenter

Answered question

2021-07-03

Find the derivatives of y with respect to the appropriate variable.
y=xsin1x+1=x2

Answer & Explanation

diskusje5

diskusje5

Skilled2021-07-04Added 82 answers

1.y=xsin1x+1x2 Given
2.dydx=[(1)(sin1x)+11x2(x)]+(12)(1x2)12(2x) Product Rule,Chain Rule, and Sum Rule
3. dydx=sin1x+x1x2x1x2 Simplification
4.dydx=sin1x Simplification

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