Question

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution,

Forms of linear equations
ANSWERED
asked 2021-06-19

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent.

\(\begin{bmatrix}1 & 0&0&|&-1 \\0 & 1&0&|&3\\0 &0 &1&|&4\\0&0&0&|&0\end{bmatrix}\)

Expert Answers (1)

2021-06-20
Bach variable is represented by a leading 1 in the corresponding column. The last row represents an equation that is always true (0=0), 20... the system is consistent and has exactly one solution.
(No parameters) Interpreting row by row as equations.
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