Each variable is represented by a leading 1, so there are no parameters needed.

There are no impossible equations , such as (0=1).

The system is consistent and has exactly one solution.

(No parameters) Interpreting row by row as equations.

Question

2021-06-24

Each variable is represented by a leading 1, so there are no parameters needed.

There are no impossible equations , such as (0=1).

The system is consistent and has exactly one solution.

(No parameters) Interpreting row by row as equations.

asked 2021-06-19

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent.

\(\begin{bmatrix}1 & 0&0&|&-1 \\0 & 1&0&|&3\\0 &0 &1&|&4\\0&0&0&|&0\end{bmatrix}\)

asked 2021-06-14

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent. [ 1 0 −1 1 0 1 2 1 ]

asked 2021-05-23

asked 2021-05-30

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Determine whether this system of linear equations is consistent and, if so, find its general solution.
Write the solution in vector form. [1−32040\000001\000000]