Question

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution,

Vectors and spaces
ANSWERED
asked 2021-06-23
The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent.

Expert Answers (1)

2021-06-24
There are two columns before the vertical bar, so there are two variables.
Each variable is represented by a leading 1, so there are no parameters needed.
There are no impossible equations , such as (0=1).
The system is consistent and has exactly one solution.
(No parameters) Interpreting row by row as equations.
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