Verify that the equation is an identity. (Hint: \cos2x=\cos(x+x).) \cos2x+2\sin^{2}x-1=0

boitshupoO

boitshupoO

Answered question

2021-06-05

Verify that the equation is an identity. (Hint: cos2x=cos(x+x).)
cos2x+2sin2x1=0

Answer & Explanation

averes8

averes8

Skilled2021-06-06Added 92 answers

Step 1
cos(2x)=cos(x+x)
=cos(x)cos(x)sin(x)sin(x)
Since cos(A+B)=cosAcosBsinAsinB]
=cos2(x)sin2(x)
cos(2x)+2sin2(x)1=cos2(x)sin2(x)+2sin2(x)1
=cos2(x)+sin2(x)1
=11
=0

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