Find the exact length of the curve x=\frac{y^4}{8}+\frac{1}{4y^2}\quad1\leq y\leq2

Dottie Parra 2021-05-18 Answered
Find the exact length of the curve
\(x=\frac{y^4}{8}+\frac{1}{4y^2}\quad1\leq y\leq2\)

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Yusuf Keller
Answered 2021-05-19 Author has 15883 answers
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