Solve the equation (3asin^2(theta)cos(theta))/(3acos^2(theta)sin(theta))

Lennie Carroll 2020-11-12 Answered

Solve the equation 3asin2(θ)cos(θ)3acos2(θ)sin(θ)=tan(θ)

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Expert Answer

Gennenzip
Answered 2020-11-13 Author has 96 answers
3asin2(θ)cos(θ)3acos2(θ)sin(θ)
=asin2(θ)cos(θ)acos2(θ)sin(θ) [Cancel the common factor 3]
=sin2(θ)cos(θ)cos2(θ)sin(θ) [Cancel the common factor a]
=sin(θ)cos(θ)cos2(θ) [Cancel the common factor sin theta]
=sin(θ)cos(θ) [Cancel the common factor cos theta]
=tanθ,Use the following identity: sin(x)cos(x)=tan(x)
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