Solve (2sinxcotx+sinx+4cotx-2)/(2cotx+1)=sinx-2

ka1leE 2021-01-05 Answered

Solve (2sinxcotx+sinx+4cotx2)/(2cotx+1)=sinx2

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Expert Answer

au4gsf
Answered 2021-01-06 Author has 95 answers

Step 1 (2sin(x)cot(x)+sin(x)4cot(x)2)/(2cot(x)+1)=Factor 2sin(x)cot(x)+sin(x)4cot(x)2:(2+sin(x))(2cot(x)+1)=((2+sin(x))(2cot(x)+1))/(2cot(x)+1)=2+sin(x) Hence, given equation is true.

Step 2

Factors of 2sin(x)cot(x)+sin(x)4cot(x)2is=2cot(x)sin(x)22cot(x)2=2cot(x)(sin(x)2)+sin(x)2=2(2+sin(x))cot(x)+1(2+sin(x))=(2+sin(x))(2cot(x)+1)(2sin(x)cot(x)+sin(x)4cot(x)2)/(2cot(x)+1)=2+sin(x)

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