What is the perimeter of the triangle below, to the nearest tenth of an inch, if each square on the grid measures 8 inches on each side?

What is the perimeter of the triangle below, to the nearest tenth of an inch, if each square on the grid measures 8 inches on each side?
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Usamah Prosser

We have a right triangle with legs measuring 2 units and 4 units. Using Pythagorean Theorem, the missing length (hypotenuse), x is:
${2}^{2}+{4}^{2}={x}^{2}$
$4+16={x}^{2}$
$20={x}^{2}$
$\surd 20=x$
So, the perimeter in terms of the number of units is:
$P=2+4+\surd 20=6+\surd 20$
Since 1 unit = 8 inches, the perimeter is:
$P=8\left(6+\surd 20\right)$
$P\approx 83.8$ inches

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