Sound waves, like light waves, can interfere with each other, giving maximum and minimum levels of sound.Suppose a listener standing directly between two loudspeakers hears the same tone being emitted from both. This listener observes that when one of the speakers is moved 0.ló m farther away, the perceived intensity of the tone decreases from a maximum to a minimum. (a) Calculate the wave length of the sound. (b) Calculate its frequency, Using 343 m s − 1 as the speed of sound.

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Sound waves, like light waves, can interfere with each other, giving maximum and minimum levels of sound.Suppose a listener standing directly between two loudspeakers hears the same tone being emitted from both. This listener observes that when one of the speakers is moved 0.ló m farther away, the perceived intensity of the tone decreases from a maximum to a minimum. (a) Calculate the wave length of the sound. (b) Calculate its frequency, Using   343  m      s          −      1       as the speed of sound.

artirw9f · Accepted Answer

λ  =  2  ×  0.16  =  0.32  m      λ    2    =  0.16  m  F  r  e  q  u  e  n  c  y  =      343    0.32    =  1.1  ×      10          3            s          −      1        F  r  e  q  u  e  n  c  y  =            V      e      l      o      c      i      t      y              W      a      v      e      l      e      n      g      t      h        V  e  l  o  c  i  t  y  =  343  m      s          −      1      Result:a. 0.32mb.   1.1  ×      10          3            s          −      1

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