The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state is: ?

Savanne1bo

Savanne1bo

Answered question

2023-01-22

The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state is:
A)194.8 nm
B)490.7 nm
C)913.3 nm
D)121.8 nm

Answer & Explanation

Dane Brennan

Dane Brennan

Beginner2023-01-23Added 9 answers

The correct answer is D)121.8 nm
Step 1: Given Data:
n 1 = 1 n 2 = 2 Z = 1
Hydrogen has an atomic number 1.
Step 2: Formula used:
1 λ = R Z 2 [ 1 n i 2 1 n h 2 ] where
λ is wavelength of the wave
R is Rydberg constant i.e. 1.097 × 10 7 m 1
Z is atomic number of the element
n i is lower energy level and n h is higher energy level.
Step 3: Calculating the wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state,
1λ=RZ2[1ni21nh2]
1λ=RZ2[1n121n22]1λ=R×(1)21121221λ=3R4λ=43RR=1.097×107m-1λ=121.8nm
Therefore, option D is the correct answer.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?