Find all values of x in the interval [0, 2pi] that satisfy the equation: 2sin^2 x=1

Caleb Proctor

Caleb Proctor

Answered question

2022-07-15

Find all values of x in the interval [ 0 , 2 π ] that satisfy the equation:
2 sin 2 x = 1

Answer & Explanation

SweallySnicles3

SweallySnicles3

Beginner2022-07-16Added 21 answers

2 sin 2 x = 1
sin 2 x = 1 2
sin x = ± 1 2
sin x = ± 1 2 2 2
sin x = ± 2 2
x = π 4 ; 7 π 4 ; 3 π 4 ; 5 π 4
Jeffrey Jordon

Jeffrey Jordon

Expert2022-08-01Added 2605 answers

Answer is given below (on video)

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