Proving 2sinx+sin2x2sinx−sin2x=csc2x+2cscxcotx+cot2x Proving right hand side to left hand side: csc2x+2cscxcotx+cot2x=1sin2x+2cosxsin2x+cos2xsin2x (1) =cos2x+2cosx+1sin2x (2) =1−sin2x+1+sin2xsinxsin2x...
Arthur Pratt
Answered
2021-12-30
Proving
Proving right hand side to left hand side:
(1)
(2)
(3)
(4)
(5)
I could not prove further to the left hand side from here.
Answer & Explanation
hysgubwyri3
Expert
2021-12-31Added 43 answers
We have that, using and cancelling out
then, assuming ( which holds since we need for the original expression), multiply by and simplify to obtain the result using that
Cheryl King
Expert
2022-01-01Added 36 answers
The following relations would be used in the answer:
Taking LHS,
Cancelling
Multiplying to numerator and denominator
which is equivalent to
Divinding each term by denominator, we get LHS as
which is the RHS.
Hence, Proved.